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Guest bigloob

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Guest jasondonervan

"Well, there doesn't seem to be any pattern yet, but if I take this one and move it here, and I move these over here.. hello! It almost looks like an arrow!"

 

"Hey, look: it's pointing right at this forum."

 

"Let's get out of here!"

 

tumblr_mdlbyz2Mqi1rw41szo1_500.png

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The only pattern I see is one with blue eyes and a tight dress.

 

 

the final codes are in rachel riley's ass

i'm going in

 

 

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I have tickets for Glastonbury this year - I'm now getting over-excited about the possibility of a surprise appearance

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I looked on the twoism forum for the first time to guage the levels of hysteria and there are some people there who think that there will be a BoC transmission saying six numbers on the advert breaks between The 10 O'Clock Show on Channel 4 tonight despite having no evidence that it will happen. They want to believe and they're all going to watch it.

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If this is the end of it all I'm going to have a good laugh about it.

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It may be possible today is slow because the other two transmissions of 6# already went out yesterday/Monday, but no one was looking in the right place.

So now it's just a waiting game until someone picks up that bizarre piece of trash sitting outside the louvre.

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Well BOC has gotten me coding for fun :D

 

My simple one-time pad WIP C++.


#include "stdafx.h"
#include <iostream>
#include <string>

using namespace std; 

int _tmain(int argc, _TCHAR* argv[])
{
	char message[30]; 
	char key[30];
	char encrypt[30]; 
	char final[30]; 
	char choices; 

	cout<<"One-Time Pad v1.1"<<endl<<"(Caps Lock must be on)"<<endl<<endl; 
	cout<<"Hit C to Crack a message or D to decrypt a message."<<endl; 
	cin>>choices; 
	cin.ignore(); 
	
	switch(choices)
	{
	case 'C':
		cout<<"Enter a message :"<<endl;
			cin.getline(message,37); 
			
		cout<<"Enter a key :"<<endl;
			cin.getline(key,37); 
	
			for(int i='A';i<='Z';i++)
				{
					for(int x=0;x<strlen(message);x++)
						{
							encrypt[x]=(message[x]+key[x])%26;
							final[x]=encrypt[x]+65; 
						}
				}

	cout<<"Encrypted word is : ";
	for(int i=0;i<strlen(message);i++){
		cout<<final[i];
	}
		cout<<endl; 
			break;
	case 'D': 
		cout<<"Enter cypher :"<<endl;
			cin.getline(encrypt,37); 

		cout<<"Enter a key :"<<endl;
			cin.getline(key,37); 
	
			//for(int i='A';i<='Z';i++)
			//	{
					for(size_t x=0;x<strlen(encrypt);x++)
						{
							if(key[x]<46)
								key[x]+26;
							message[x]=(encrypt[x]-key[x])%26;
							final[x]=message[x]+65; 
							
							
						}
			//	}
		

	cout<<"Decrypted message is : ";
	for(size_t i=0;i<strlen(encrypt);i++){
		cout<<final[i];
	}
		cout<<endl;
			break; 
		}

	return 0;
}

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Guest liquiday

 

Well BOC has gotten me coding for fun :D

 

My simple one-time pad WIP C++.


#include "stdafx.h"
#include <iostream>
#include <string>

using namespace std; 

int _tmain(int argc, _TCHAR* argv[])
{
	char message[30]; 
	char key[30];
	char encrypt[30]; 
	char final[30]; 
	char choices; 

	cout<<"One-Time Pad v1.1"<<endl<<"(Caps Lock must be on)"<<endl<<endl; 
	cout<<"Hit C to Crack a message or D to decrypt a message."<<endl; 
	cin>>choices; 
	cin.ignore(); 
	
	switch(choices)
	{
	case 'C':
		cout<<"Enter a message :"<<endl;
			cin.getline(message,37); 
			
		cout<<"Enter a key :"<<endl;
			cin.getline(key,37); 
	
			for(int i='A';i<='Z';i++)
				{
					for(int x=0;x<strlen(message);x++)
						{
							encrypt[x]=(message[x]+key[x])%26;
							final[x]=encrypt[x]+65; 
						}
				}

	cout<<"Encrypted word is : ";
	for(int i=0;i<strlen(message);i++){
		cout<<final[i];
	}
		cout<<endl; 
			break;
	case 'D': 
		cout<<"Enter cypher :"<<endl;
			cin.getline(encrypt,37); 

		cout<<"Enter a key :"<<endl;
			cin.getline(key,37); 
	
			//for(int i='A';i<='Z';i++)
			//	{
					for(size_t x=0;x<strlen(encrypt);x++)
						{
							if(key[x]<46)
								key[x]+26;
							message[x]=(encrypt[x]-key[x])%26;
							final[x]=message[x]+65; 
							
							
						}
			//	}
		

	cout<<"Decrypted message is : ";
	for(size_t i=0;i<strlen(encrypt);i++){
		cout<<final[i];
	}
		cout<<endl;
			break; 
		}

	return 0;
}

cout<<"No new album in 2013"<<endl;

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